-6(3y-3)+9y=6(y+2)

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Solution for -6(3y-3)+9y=6(y+2) equation: 



-6(3y-3)+9y=6(y+2)

We move all terms to the left:

-6(3y-3)+9y-(6(y+2))=0

We add all the numbers together, and all the variables

9y-6(3y-3)-(6(y+2))=0

We multiply parentheses

9y-18y-(6(y+2))+18=0



We calculate terms in parentheses: -(6(y+2)), so:

6(y+2)

We multiply parentheses

6y+12

Back to the equation:

-(6y+12)



We add all the numbers together, and all the variables

-9y-(6y+12)+18=0

We get rid of parentheses

-9y-6y-12+18=0

We add all the numbers together, and all the variables

-15y+6=0

We move all terms containing y to the left, all other terms to the right

-15y=-6

y=-6/-15

y=2/5

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