-6(3x-5)=40-8x=

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Solution for -6(3x-5)=40-8x= equation: 



-6(3x-5)=40-8x=

We move all terms to the left:

-6(3x-5)-(40-8x)=0

We add all the numbers together, and all the variables

-6(3x-5)-(-8x+40)=0

We multiply parentheses

-18x-(-8x+40)+30=0

We get rid of parentheses

-18x+8x-40+30=0

We add all the numbers together, and all the variables

-10x-10=0

We move all terms containing x to the left, all other terms to the right

-10x=10

x=10/-10

x=-1

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