-6(3b-2)+2=-6b+47

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Solution for -6(3b-2)+2=-6b+47 equation: 



-6(3b-2)+2=-6b+47

We move all terms to the left:

-6(3b-2)+2-(-6b+47)=0

We multiply parentheses

-18b-(-6b+47)+12+2=0

We get rid of parentheses

-18b+6b-47+12+2=0

We add all the numbers together, and all the variables

-12b-33=0

We move all terms containing b to the left, all other terms to the right

-12b=33

b=33/-12

b=-2+3/4

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