-6(3-v)=10+2v

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Solution for -6(3-v)=10+2v equation: 



-6(3-v)=10+2v

We move all terms to the left:

-6(3-v)-(10+2v)=0

We add all the numbers together, and all the variables

-6(-1v+3)-(2v+10)=0

We multiply parentheses

6v-(2v+10)-18=0

We get rid of parentheses

6v-2v-10-18=0

We add all the numbers together, and all the variables

4v-28=0

We move all terms containing v to the left, all other terms to the right

4v=28

v=28/4

v=7

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