-6(2t-+1)=-18

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Solution for -6(2t-+1)=-18 equation: 



-6(2t-+1)=-18

We move all terms to the left:

-6(2t-+1)-(-18)=0

We add all the numbers together, and all the variables

-6(+2t)-(-18)=0

We add all the numbers together, and all the variables

-6(+2t)+18=0

We multiply parentheses

-12t+18=0

We move all terms containing t to the left, all other terms to the right

-12t=-18

t=-18/-12

t=1+1/2

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