-6(10+2x)=28+x

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Solution for -6(10+2x)=28+x equation: 



-6(10+2x)=28+x

We move all terms to the left:

-6(10+2x)-(28+x)=0

We add all the numbers together, and all the variables

-6(2x+10)-(x+28)=0

We multiply parentheses

-12x-(x+28)-60=0

We get rid of parentheses

-12x-x-28-60=0

We add all the numbers together, and all the variables

-13x-88=0

We move all terms containing x to the left, all other terms to the right

-13x=88

x=88/-13

x=-6+10/13

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