-6(1+2v)=-3(2+4v)

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Solution for -6(1+2v)=-3(2+4v) equation: 



-6(1+2v)=-3(2+4v)

We move all terms to the left:

-6(1+2v)-(-3(2+4v))=0

We add all the numbers together, and all the variables

-6(2v+1)-(-3(4v+2))=0

We multiply parentheses

-12v-(-3(4v+2))-6=0



We calculate terms in parentheses: -(-3(4v+2)), so:

-3(4v+2)

We multiply parentheses

-12v-6

Back to the equation:

-(-12v-6)



We get rid of parentheses

-12v+12v+6-6=0

We add all the numbers together, and all the variables

=0

v=0/1

v=0

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