-6(1+2r)+5r=5(1-2r)+4r

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Solution for -6(1+2r)+5r=5(1-2r)+4r equation: 



-6(1+2r)+5r=5(1-2r)+4r

We move all terms to the left:

-6(1+2r)+5r-(5(1-2r)+4r)=0

We add all the numbers together, and all the variables

-6(2r+1)+5r-(5(-2r+1)+4r)=0

We add all the numbers together, and all the variables

5r-6(2r+1)-(5(-2r+1)+4r)=0

We multiply parentheses

5r-12r-(5(-2r+1)+4r)-6=0



We calculate terms in parentheses: -(5(-2r+1)+4r), so:

5(-2r+1)+4r

We add all the numbers together, and all the variables

4r+5(-2r+1)

We multiply parentheses

4r-10r+5

We add all the numbers together, and all the variables

-6r+5

Back to the equation:

-(-6r+5)



We add all the numbers together, and all the variables

-7r-(-6r+5)-6=0

We get rid of parentheses

-7r+6r-5-6=0

We add all the numbers together, and all the variables

-1r-11=0

We move all terms containing r to the left, all other terms to the right

-r=11

r=11/-1

r=-11

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