-6(-u+1)=2(1-3u)-7

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Solution for -6(-u+1)=2(1-3u)-7 equation: 



-6(-u+1)=2(1-3u)-7

We move all terms to the left:

-6(-u+1)-(2(1-3u)-7)=0

We add all the numbers together, and all the variables

-6(-1u+1)-(2(-3u+1)-7)=0

We multiply parentheses

6u-(2(-3u+1)-7)-6=0



We calculate terms in parentheses: -(2(-3u+1)-7), so:

2(-3u+1)-7

We multiply parentheses

-6u+2-7

We add all the numbers together, and all the variables

-6u-5

Back to the equation:

-(-6u-5)



We get rid of parentheses

6u+6u+5-6=0

We add all the numbers together, and all the variables

12u-1=0

We move all terms containing u to the left, all other terms to the right

12u=1

u=1/12

u=1/12

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