-6(-5y+4)-8y=7(y-4)-5

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Solution for -6(-5y+4)-8y=7(y-4)-5 equation: 



-6(-5y+4)-8y=7(y-4)-5

We move all terms to the left:

-6(-5y+4)-8y-(7(y-4)-5)=0

We add all the numbers together, and all the variables

-8y-6(-5y+4)-(7(y-4)-5)=0

We multiply parentheses

-8y+30y-(7(y-4)-5)-24=0



We calculate terms in parentheses: -(7(y-4)-5), so:

7(y-4)-5

We multiply parentheses

7y-28-5

We add all the numbers together, and all the variables

7y-33

Back to the equation:

-(7y-33)



We add all the numbers together, and all the variables

22y-(7y-33)-24=0

We get rid of parentheses

22y-7y+33-24=0

We add all the numbers together, and all the variables

15y+9=0

We move all terms containing y to the left, all other terms to the right

15y=-9

y=-9/15

y=-3/5

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