-6(-3-k)-1=4(k-2)-3k

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Solution for -6(-3-k)-1=4(k-2)-3k equation: 



-6(-3-k)-1=4(k-2)-3k

We move all terms to the left:

-6(-3-k)-1-(4(k-2)-3k)=0

We add all the numbers together, and all the variables

-6(-1k-3)-(4(k-2)-3k)-1=0

We multiply parentheses

6k-(4(k-2)-3k)+18-1=0



We calculate terms in parentheses: -(4(k-2)-3k), so:

4(k-2)-3k

We add all the numbers together, and all the variables

-3k+4(k-2)

We multiply parentheses

-3k+4k-8

We add all the numbers together, and all the variables

k-8

Back to the equation:

-(k-8)



We add all the numbers together, and all the variables

6k-(k-8)+17=0

We get rid of parentheses

6k-k+8+17=0

We add all the numbers together, and all the variables

5k+25=0

We move all terms containing k to the left, all other terms to the right

5k=-25

k=-25/5

k=-5

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