-6(-2u+4)-5u=3(u-5)-3

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Solution for -6(-2u+4)-5u=3(u-5)-3 equation: 



-6(-2u+4)-5u=3(u-5)-3

We move all terms to the left:

-6(-2u+4)-5u-(3(u-5)-3)=0

We add all the numbers together, and all the variables

-5u-6(-2u+4)-(3(u-5)-3)=0

We multiply parentheses

-5u+12u-(3(u-5)-3)-24=0



We calculate terms in parentheses: -(3(u-5)-3), so:

3(u-5)-3

We multiply parentheses

3u-15-3

We add all the numbers together, and all the variables

3u-18

Back to the equation:

-(3u-18)



We add all the numbers together, and all the variables

7u-(3u-18)-24=0

We get rid of parentheses

7u-3u+18-24=0

We add all the numbers together, and all the variables

4u-6=0

We move all terms containing u to the left, all other terms to the right

4u=6

u=6/4

u=1+1/2

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