-6(-1-2n)+2n=12n-2(n-1)

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Solution for -6(-1-2n)+2n=12n-2(n-1) equation: 



-6(-1-2n)+2n=12n-2(n-1)

We move all terms to the left:

-6(-1-2n)+2n-(12n-2(n-1))=0

We add all the numbers together, and all the variables

-6(-2n-1)+2n-(12n-2(n-1))=0

We add all the numbers together, and all the variables

2n-6(-2n-1)-(12n-2(n-1))=0

We multiply parentheses

2n+12n-(12n-2(n-1))+6=0



We calculate terms in parentheses: -(12n-2(n-1)), so:

12n-2(n-1)

We multiply parentheses

12n-2n+2

We add all the numbers together, and all the variables

10n+2

Back to the equation:

-(10n+2)



We add all the numbers together, and all the variables

14n-(10n+2)+6=0

We get rid of parentheses

14n-10n-2+6=0

We add all the numbers together, and all the variables

4n+4=0

We move all terms containing n to the left, all other terms to the right

4n=-4

n=-4/4

n=-1

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