-5y-3(9y+3)=1-1(-1-y)y=

Solution for -5y-3(9y+3)=1-1(-1-y)y= equation:

-5y-3(9y+3)=1-1(-1-y)y=

We move all terms to the left:

-5y-3(9y+3)-(1-1(-1-y)y)=0

We add all the numbers together, and all the variables

-5y-3(9y+3)-(1-1(-1y-1)y)=0

We multiply parentheses

-5y-27y-(1-1(-1y-1)y)-9=0


We calculate terms in parentheses: -(1-1(-1y-1)y), so:

1-1(-1y-1)y

determiningTheFunctionDomain
-1(-1y-1)y+1

We multiply parentheses

1y^2+1y+1

We add all the numbers together, and all the variables

y^2+y+1

Back to the equation:

-(y^2+y+1)


We add all the numbers together, and all the variables

-32y-(y^2+y+1)-9=0

We get rid of parentheses

-y^2-32y-y-1-9=0

We add all the numbers together, and all the variables

-1y^2-33y-10=0

a = -1; b = -33; c = -10;
Δ = b2-4ac
Δ = -332-4·(-1)·(-10)
Δ = 1049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-\sqrt{1049}}{2*-1}=\frac{33-\sqrt{1049}}{-2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+\sqrt{1049}}{2*-1}=\frac{33+\sqrt{1049}}{-2}
$