-5y+32=-7(y-2)

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Solution for -5y+32=-7(y-2) equation: 



-5y+32=-7(y-2)

We move all terms to the left:

-5y+32-(-7(y-2))=0



We calculate terms in parentheses: -(-7(y-2)), so:

-7(y-2)

We multiply parentheses

-7y+14

Back to the equation:

-(-7y+14)



We get rid of parentheses

-5y+7y-14+32=0

We add all the numbers together, and all the variables

2y+18=0

We move all terms containing y to the left, all other terms to the right

2y=-18

y=-18/2

y=-9

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