-5y(-4y+3)-y=4(y-1)-1

Solution for -5y(-4y+3)-y=4(y-1)-1 equation:

-5y(-4y+3)-y=4(y-1)-1

We move all terms to the left:

-5y(-4y+3)-y-(4(y-1)-1)=0

We add all the numbers together, and all the variables

-1y-5y(-4y+3)-(4(y-1)-1)=0

We multiply parentheses

20y^2-1y-15y-(4(y-1)-1)=0


We calculate terms in parentheses: -(4(y-1)-1), so:

4(y-1)-1

We multiply parentheses

4y-4-1

We add all the numbers together, and all the variables

4y-5

Back to the equation:

-(4y-5)


We add all the numbers together, and all the variables

20y^2-16y-(4y-5)=0

We get rid of parentheses

20y^2-16y-4y+5=0

We add all the numbers together, and all the variables

20y^2-20y+5=0

a = 20; b = -20; c = +5;
Δ = b2-4ac
Δ = -202-4·20·5
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{20}{40}=1/2$