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-5y(-30-10y)=0
We add all the numbers together, and all the variables
-5y(-10y-30)=0
We multiply parentheses
50y^2+150y=0
a = 50; b = 150; c = 0;
Δ = b2-4ac
Δ = 1502-4·50·0
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{22500}=150$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(150)-150}{2*50}=\frac{-300}{100} =-3 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(150)+150}{2*50}=\frac{0}{100} =0 $
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