-5x-(7-4x)=-2x(3x-4)

Solution for -5x-(7-4x)=-2x(3x-4) equation:

-5x-(7-4x)=-2x(3x-4)

We move all terms to the left:

-5x-(7-4x)-(-2x(3x-4))=0

We add all the numbers together, and all the variables

-5x-(-4x+7)-(-2x(3x-4))=0

We get rid of parentheses

-5x+4x-(-2x(3x-4))-7=0


We calculate terms in parentheses: -(-2x(3x-4)), so:

-2x(3x-4)

We multiply parentheses

-6x^2+8x

Back to the equation:

-(-6x^2+8x)


We add all the numbers together, and all the variables

-(-6x^2+8x)-1x-7=0

We get rid of parentheses

6x^2-8x-1x-7=0

We add all the numbers together, and all the variables

6x^2-9x-7=0

a = 6; b = -9; c = -7;
Δ = b2-4ac
Δ = -92-4·6·(-7)
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{249}}{2*6}=\frac{9-\sqrt{249}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{249}}{2*6}=\frac{9+\sqrt{249}}{12}
$