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-5x(x-10)=-35
We move all terms to the left:
-5x(x-10)-(-35)=0
We add all the numbers together, and all the variables
-5x(x-10)+35=0
We multiply parentheses
-5x^2+50x+35=0
a = -5; b = 50; c = +35;
Δ = b2-4ac
Δ = 502-4·(-5)·35
Δ = 3200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3200}=\sqrt{1600*2}=\sqrt{1600}*\sqrt{2}=40\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-40\sqrt{2}}{2*-5}=\frac{-50-40\sqrt{2}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+40\sqrt{2}}{2*-5}=\frac{-50+40\sqrt{2}}{-10} $
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