-5x(x+4)=20

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Solution for -5x(x+4)=20 equation: 



-5x(x+4)=20

We move all terms to the left:

-5x(x+4)-(20)=0

We multiply parentheses

-5x^2-20x-20=0

a = -5; b = -20; c = -20;
Δ = b2-4ac
Δ = -202-4·(-5)·(-20)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{20}{-10}=-2$

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