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-5x(-3x-2)=-19x-6
We move all terms to the left:
-5x(-3x-2)-(-19x-6)=0
We multiply parentheses
15x^2+10x-(-19x-6)=0
We get rid of parentheses
15x^2+10x+19x+6=0
We add all the numbers together, and all the variables
15x^2+29x+6=0
a = 15; b = 29; c = +6;
Δ = b2-4ac
Δ = 292-4·15·6
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{481}}{2*15}=\frac{-29-\sqrt{481}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{481}}{2*15}=\frac{-29+\sqrt{481}}{30} $
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