-5r+3(r-5)=-(2r+15)

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Solution for -5r+3(r-5)=-(2r+15) equation: 



-5r+3(r-5)=-(2r+15)

We move all terms to the left:

-5r+3(r-5)-(-(2r+15))=0

We multiply parentheses

-5r+3r-(-(2r+15))-15=0



We calculate terms in parentheses: -(-(2r+15)), so:

-(2r+15)

We get rid of parentheses

-2r-15

Back to the equation:

-(-2r-15)



We add all the numbers together, and all the variables

-2r-(-2r-15)-15=0

We get rid of parentheses

-2r+2r+15-15=0

We add all the numbers together, and all the variables

=0

r=0/1

r=0

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