-5q+7+3q-4=-6(12q-8+28)+13q

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Solution for -5q+7+3q-4=-6(12q-8+28)+13q equation: 



-5q+7+3q-4=-6(12q-8+28)+13q

We move all terms to the left:

-5q+7+3q-4-(-6(12q-8+28)+13q)=0

We add all the numbers together, and all the variables

-5q+3q-(-6(12q+20)+13q)+7-4=0

We add all the numbers together, and all the variables

-2q-(-6(12q+20)+13q)+3=0



We calculate terms in parentheses: -(-6(12q+20)+13q), so:

-6(12q+20)+13q

We add all the numbers together, and all the variables

13q-6(12q+20)

We multiply parentheses

13q-72q-120

We add all the numbers together, and all the variables

-59q-120

Back to the equation:

-(-59q-120)



We get rid of parentheses

-2q+59q+120+3=0

We add all the numbers together, and all the variables

57q+123=0

We move all terms containing q to the left, all other terms to the right

57q=-123

q=-123/57

q=-2+3/19

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