-5q(3q-6)=-45

Solution for -5q(3q-6)=-45 equation:

-5q(3q-6)=-45

We move all terms to the left:

-5q(3q-6)-(-45)=0

We add all the numbers together, and all the variables

-5q(3q-6)+45=0

We multiply parentheses

-15q^2+30q+45=0

a = -15; b = 30; c = +45;
Δ = b2-4ac
Δ = 302-4·(-15)·45
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-60}{2*-15}=\frac{-90}{-30}
=+3
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+60}{2*-15}=\frac{30}{-30}
=-1
$