-5=m(2)+5

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Solution for -5=m(2)+5 equation: 



-5=m(2)+5

We move all terms to the left:

-5-(m(2)+5)=0

We add all the numbers together, and all the variables

-(+m^2+5)-5=0

We get rid of parentheses

-m^2-5-5=0

We add all the numbers together, and all the variables

-1m^2-10=0

a = -1; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·(-1)·(-10)
Δ = -40
Delta is less than zero, so there is no solution for the equation

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