-52+42z=6(7z-9)+2

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Solution for -52+42z=6(7z-9)+2 equation: 



-52+42z=6(7z-9)+2

We move all terms to the left:

-52+42z-(6(7z-9)+2)=0



We calculate terms in parentheses: -(6(7z-9)+2), so:

6(7z-9)+2

We multiply parentheses

42z-54+2

We add all the numbers together, and all the variables

42z-52

Back to the equation:

-(42z-52)



We get rid of parentheses

42z-42z+52-52=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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