-50=5/6(12-18d)

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Solution for -50=5/6(12-18d) equation: 



-50=5/6(12-18d)

We move all terms to the left:

-50-(5/6(12-18d))=0



Domain of the equation: 6(12-18d))!=0

d∈R



We add all the numbers together, and all the variables

-(5/6(-18d+12))-50=0

We multiply all the terms by the denominator


-(5-50*6(-18d+12))=0



We calculate terms in parentheses: -(5-50*6(-18d+12)), so:

5-50*6(-18d+12)

determiningTheFunctionDomain
-50*6(-18d+12)+5

Wy multiply elements

-300d(-+5

We use the square of the difference formula

-300d(-5

Back to the equation:

-(-300d(-5)





We calculate terms in parentheses: -(-300d(-5), so:

-300d(-5





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-300d(-5





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-300d(-5





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-300d(-5





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-300d(-5





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-300d(-5





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-300d(-5





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-300d(-5





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-300d(-5





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-300d(-5





We calculate terms in parentheses: -(-300d(-5), so:

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-300d(-5





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We calculate terms in parentheses: -(-300d(-5), so:

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