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-5/w-3/5w=-4/3
We move all terms to the left:
-5/w-3/5w-(-4/3)=0
Domain of the equation: w!=0
w∈R
Domain of the equation: 5w!=0We get rid of parentheses
w!=0/5
w!=0
w∈R
-5/w-3/5w+4/3=0
We calculate fractions
100w^2/45w^2+(-225w)/45w^2+(-27w)/45w^2=0
We multiply all the terms by the denominator
100w^2+(-225w)+(-27w)=0
We get rid of parentheses
100w^2-225w-27w=0
We add all the numbers together, and all the variables
100w^2-252w=0
a = 100; b = -252; c = 0;
Δ = b2-4ac
Δ = -2522-4·100·0
Δ = 63504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{63504}=252$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-252)-252}{2*100}=\frac{0}{200} =0 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-252)+252}{2*100}=\frac{504}{200} =2+13/25 $
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