-5/8x+10+x=-8

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Solution for -5/8x+10+x=-8 equation:



-5/8x+10+x=-8
We move all terms to the left:
-5/8x+10+x-(-8)=0
Domain of the equation: 8x!=0
x!=0/8
x!=0
x∈R
We add all the numbers together, and all the variables
x-5/8x+18=0
We multiply all the terms by the denominator
x*8x+18*8x-5=0
Wy multiply elements
8x^2+144x-5=0
a = 8; b = 144; c = -5;
Δ = b2-4ac
Δ = 1442-4·8·(-5)
Δ = 20896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{20896}=\sqrt{16*1306}=\sqrt{16}*\sqrt{1306}=4\sqrt{1306}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(144)-4\sqrt{1306}}{2*8}=\frac{-144-4\sqrt{1306}}{16} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(144)+4\sqrt{1306}}{2*8}=\frac{-144+4\sqrt{1306}}{16} $

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