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-5/6x-1/8x=-102
We move all terms to the left:
-5/6x-1/8x-(-102)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 8x!=0We add all the numbers together, and all the variables
x!=0/8
x!=0
x∈R
-5/6x-1/8x+102=0
We calculate fractions
(-40x)/48x^2+(-6x)/48x^2+102=0
We multiply all the terms by the denominator
(-40x)+(-6x)+102*48x^2=0
Wy multiply elements
4896x^2+(-40x)+(-6x)=0
We get rid of parentheses
4896x^2-40x-6x=0
We add all the numbers together, and all the variables
4896x^2-46x=0
a = 4896; b = -46; c = 0;
Δ = b2-4ac
Δ = -462-4·4896·0
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-46}{2*4896}=\frac{0}{9792} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+46}{2*4896}=\frac{92}{9792} =23/2448 $
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