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-5/6x+4=5/2x
We move all terms to the left:
-5/6x+4-(5/2x)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-5/6x-(+5/2x)+4=0
We get rid of parentheses
-5/6x-5/2x+4=0
We calculate fractions
(-10x)/12x^2+(-30x)/12x^2+4=0
We multiply all the terms by the denominator
(-10x)+(-30x)+4*12x^2=0
Wy multiply elements
48x^2+(-10x)+(-30x)=0
We get rid of parentheses
48x^2-10x-30x=0
We add all the numbers together, and all the variables
48x^2-40x=0
a = 48; b = -40; c = 0;
Δ = b2-4ac
Δ = -402-4·48·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-40}{2*48}=\frac{0}{96} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+40}{2*48}=\frac{80}{96} =5/6 $
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