-5/6x+2=1/3x-5

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Solution for -5/6x+2=1/3x-5 equation:



-5/6x+2=1/3x-5
We move all terms to the left:
-5/6x+2-(1/3x-5)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 3x-5)!=0
x∈R
We get rid of parentheses
-5/6x-1/3x+5+2=0
We calculate fractions
(-15x)/18x^2+(-6x)/18x^2+5+2=0
We add all the numbers together, and all the variables
(-15x)/18x^2+(-6x)/18x^2+7=0
We multiply all the terms by the denominator
(-15x)+(-6x)+7*18x^2=0
Wy multiply elements
126x^2+(-15x)+(-6x)=0
We get rid of parentheses
126x^2-15x-6x=0
We add all the numbers together, and all the variables
126x^2-21x=0
a = 126; b = -21; c = 0;
Δ = b2-4ac
Δ = -212-4·126·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-21}{2*126}=\frac{0}{252} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+21}{2*126}=\frac{42}{252} =1/6 $

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