-5/6c-2/3c=-24

Solution for -5/6c-2/3c=-24 equation:

-5/6c-2/3c=-24

We move all terms to the left:

-5/6c-2/3c-(-24)=0


Domain of the equation: 6c!=0

c!=0/6

c!=0

c∈R



Domain of the equation: 3c!=0

c!=0/3

c!=0

c∈R


We add all the numbers together, and all the variables

-5/6c-2/3c+24=0

We calculate fractions


(-15c)/18c^2+(-12c)/18c^2+24=0

We multiply all the terms by the denominator


(-15c)+(-12c)+24*18c^2=0

Wy multiply elements

432c^2+(-15c)+(-12c)=0

We get rid of parentheses

432c^2-15c-12c=0

We add all the numbers together, and all the variables

432c^2-27c=0

a = 432; b = -27; c = 0;
Δ = b2-4ac
Δ = -272-4·432·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-27}{2*432}=\frac{0}{864}
=0
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+27}{2*432}=\frac{54}{864}
=1/16
$