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-5/4x+5/3x=-35/36
We move all terms to the left:
-5/4x+5/3x-(-35/36)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
-5/4x+5/3x+35/36=0
We calculate fractions
1260x^2/1296x^2+(-1620x)/1296x^2+2160x/1296x^2=0
We multiply all the terms by the denominator
1260x^2+(-1620x)+2160x=0
We add all the numbers together, and all the variables
1260x^2+2160x+(-1620x)=0
We get rid of parentheses
1260x^2+2160x-1620x=0
We add all the numbers together, and all the variables
1260x^2+540x=0
a = 1260; b = 540; c = 0;
Δ = b2-4ac
Δ = 5402-4·1260·0
Δ = 291600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{291600}=540$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(540)-540}{2*1260}=\frac{-1080}{2520} =-3/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(540)+540}{2*1260}=\frac{0}{2520} =0 $
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