-5/4c-1/2=-3+5/8c

Solution for -5/4c-1/2=-3+5/8c equation:

-5/4c-1/2=-3+5/8c

We move all terms to the left:

-5/4c-1/2-(-3+5/8c)=0


Domain of the equation: 4c!=0

c!=0/4

c!=0

c∈R



Domain of the equation: 8c)!=0

c!=0/1

c!=0

c∈R


We add all the numbers together, and all the variables

-5/4c-(5/8c-3)-1/2=0

We get rid of parentheses

-5/4c-5/8c+3-1/2=0

We calculate fractions


(-256c^2)/128c^2+(-160c)/128c^2+(-80c)/128c^2+3=0

We multiply all the terms by the denominator


(-256c^2)+(-160c)+(-80c)+3*128c^2=0

Wy multiply elements

(-256c^2)+384c^2+(-160c)+(-80c)=0

We get rid of parentheses

-256c^2+384c^2-160c-80c=0

We add all the numbers together, and all the variables

128c^2-240c=0

a = 128; b = -240; c = 0;
Δ = b2-4ac
Δ = -2402-4·128·0
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-240)-240}{2*128}=\frac{0}{256}
=0
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-240)+240}{2*128}=\frac{480}{256}
=1+7/8
$