-5/(n-4)=-6/(n+1)

Solution for -5/(n-4)=-6/(n+1) equation:

-5/(n-4)=-6/(n+1)

We move all terms to the left:

-5/(n-4)-(-6/(n+1))=0


Domain of the equation: (n-4)!=0

We move all terms containing n to the left, all other terms to the right

n!=4

n∈R



Domain of the equation: (n+1))!=0

n∈R


We calculate fractions


(-5n)/((n-4)*(n+1)))+(-(-6*(n-4))/((n-4)*(n+1)))=0


We calculate terms in parentheses: -(-6*(n-4))/((n-4)*(n+1))), so:

-6*(n-4))/((n-4)*(n+1))

We multiply all the terms by the denominator


-6*(n-4))

We multiply parentheses

-6n-

We add all the numbers together, and all the variables

-6n

Back to the equation:

-(-6n)


We get rid of parentheses

(-5n)/((n-4)*(n+1)))+(+6n=0

We multiply all the terms by the denominator


(-5n)+6n*((n-4)*(n+1)))+(=0

We get rid of parentheses

-5n+6n*((n-4)*(n+1)))+(=0