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-5-r=1/2r
We move all terms to the left:
-5-r-(1/2r)=0
Domain of the equation: 2r)!=0We add all the numbers together, and all the variables
r!=0/1
r!=0
r∈R
-r-(+1/2r)-5=0
We add all the numbers together, and all the variables
-1r-(+1/2r)-5=0
We get rid of parentheses
-1r-1/2r-5=0
We multiply all the terms by the denominator
-1r*2r-5*2r-1=0
Wy multiply elements
-2r^2-10r-1=0
a = -2; b = -10; c = -1;
Δ = b2-4ac
Δ = -102-4·(-2)·(-1)
Δ = 92
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{92}=\sqrt{4*23}=\sqrt{4}*\sqrt{23}=2\sqrt{23}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{23}}{2*-2}=\frac{10-2\sqrt{23}}{-4} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{23}}{2*-2}=\frac{10+2\sqrt{23}}{-4} $
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