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-5-2n^2=-63
We move all terms to the left:
-5-2n^2-(-63)=0
We add all the numbers together, and all the variables
-2n^2+58=0
a = -2; b = 0; c = +58;
Δ = b2-4ac
Δ = 02-4·(-2)·58
Δ = 464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{464}=\sqrt{16*29}=\sqrt{16}*\sqrt{29}=4\sqrt{29}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{29}}{2*-2}=\frac{0-4\sqrt{29}}{-4} =-\frac{4\sqrt{29}}{-4} =-\frac{\sqrt{29}}{-1} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{29}}{2*-2}=\frac{0+4\sqrt{29}}{-4} =\frac{4\sqrt{29}}{-4} =\frac{\sqrt{29}}{-1} $
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