-5(z+2)+3(4z-4)=6(z-4)+8

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Solution for -5(z+2)+3(4z-4)=6(z-4)+8 equation: 



-5(z+2)+3(4z-4)=6(z-4)+8

We move all terms to the left:

-5(z+2)+3(4z-4)-(6(z-4)+8)=0

We multiply parentheses

-5z+12z-(6(z-4)+8)-10-12=0



We calculate terms in parentheses: -(6(z-4)+8), so:

6(z-4)+8

We multiply parentheses

6z-24+8

We add all the numbers together, and all the variables

6z-16

Back to the equation:

-(6z-16)



We add all the numbers together, and all the variables

7z-(6z-16)-22=0

We get rid of parentheses

7z-6z+16-22=0

We add all the numbers together, and all the variables

z-6=0

We move all terms containing z to the left, all other terms to the right

z=6

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