-5(y-5)=3y+41

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Solution for -5(y-5)=3y+41 equation: 



-5(y-5)=3y+41

We move all terms to the left:

-5(y-5)-(3y+41)=0

We multiply parentheses

-5y-(3y+41)+25=0

We get rid of parentheses

-5y-3y-41+25=0

We add all the numbers together, and all the variables

-8y-16=0

We move all terms containing y to the left, all other terms to the right

-8y=16

y=16/-8

y=-2

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