-5(y+2)+3(3y-7)=3(y-4)+10

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Solution for -5(y+2)+3(3y-7)=3(y-4)+10 equation: 



-5(y+2)+3(3y-7)=3(y-4)+10

We move all terms to the left:

-5(y+2)+3(3y-7)-(3(y-4)+10)=0

We multiply parentheses

-5y+9y-(3(y-4)+10)-10-21=0



We calculate terms in parentheses: -(3(y-4)+10), so:

3(y-4)+10

We multiply parentheses

3y-12+10

We add all the numbers together, and all the variables

3y-2

Back to the equation:

-(3y-2)



We add all the numbers together, and all the variables

4y-(3y-2)-31=0

We get rid of parentheses

4y-3y+2-31=0

We add all the numbers together, and all the variables

y-29=0

We move all terms containing y to the left, all other terms to the right

y=29

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