-5(y+1)=3y-9+2(4y+6)

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Solution for -5(y+1)=3y-9+2(4y+6) equation: 



-5(y+1)=3y-9+2(4y+6)

We move all terms to the left:

-5(y+1)-(3y-9+2(4y+6))=0

We multiply parentheses

-5y-(3y-9+2(4y+6))-5=0



We calculate terms in parentheses: -(3y-9+2(4y+6)), so:

3y-9+2(4y+6)

determiningTheFunctionDomain
3y+2(4y+6)-9

We multiply parentheses

3y+8y+12-9

We add all the numbers together, and all the variables

11y+3

Back to the equation:

-(11y+3)



We get rid of parentheses

-5y-11y-3-5=0

We add all the numbers together, and all the variables

-16y-8=0

We move all terms containing y to the left, all other terms to the right

-16y=8

y=8/-16

y=-1/2

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