-5(x+3)+3(3x-4)=3(x-3)+10

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Solution for -5(x+3)+3(3x-4)=3(x-3)+10 equation: 



-5(x+3)+3(3x-4)=3(x-3)+10

We move all terms to the left:

-5(x+3)+3(3x-4)-(3(x-3)+10)=0

We multiply parentheses

-5x+9x-(3(x-3)+10)-15-12=0



We calculate terms in parentheses: -(3(x-3)+10), so:

3(x-3)+10

We multiply parentheses

3x-9+10

We add all the numbers together, and all the variables

3x+1

Back to the equation:

-(3x+1)



We add all the numbers together, and all the variables

4x-(3x+1)-27=0

We get rid of parentheses

4x-3x-1-27=0

We add all the numbers together, and all the variables

x-28=0

We move all terms containing x to the left, all other terms to the right

x=28

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