-5(x+1)+3x=6x(4x-3)

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Solution for -5(x+1)+3x=6x(4x-3) equation: 



-5(x+1)+3x=6x(4x-3)

We move all terms to the left:

-5(x+1)+3x-(6x(4x-3))=0

We add all the numbers together, and all the variables

3x-5(x+1)-(6x(4x-3))=0

We multiply parentheses

3x-5x-(6x(4x-3))-5=0



We calculate terms in parentheses: -(6x(4x-3)), so:

6x(4x-3)

We multiply parentheses

24x^2-18x

Back to the equation:

-(24x^2-18x)



We add all the numbers together, and all the variables

-2x-(24x^2-18x)-5=0

We get rid of parentheses

-24x^2-2x+18x-5=0

We add all the numbers together, and all the variables

-24x^2+16x-5=0

a = -24; b = 16; c = -5;
Δ = b2-4ac
Δ = 162-4·(-24)·(-5)
Δ = -224
Delta is less than zero, so there is no solution for the equation

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