-5(x+1)+3x=6+-(4x-3)

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Solution for -5(x+1)+3x=6+-(4x-3) equation: 



-5(x+1)+3x=6+-(4x-3)

We move all terms to the left:

-5(x+1)+3x-(6+-(4x-3))=0

We add all the numbers together, and all the variables

3x-5(x+1)-(6+-(4x-3))=0

We use the square of the difference formula

3x-5(x+1)-(6-(4x-3))=0

We multiply parentheses

3x-5x-(6-(4x-3))-5=0



We calculate terms in parentheses: -(6-(4x-3)), so:

6-(4x-3)

determiningTheFunctionDomain
-(4x-3)+6

We get rid of parentheses

-4x+3+6

We add all the numbers together, and all the variables

-4x+9

Back to the equation:

-(-4x+9)



We add all the numbers together, and all the variables

-2x-(-4x+9)-5=0

We get rid of parentheses

-2x+4x-9-5=0

We add all the numbers together, and all the variables

2x-14=0

We move all terms containing x to the left, all other terms to the right

2x=14

x=14/2

x=7

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