-5(w+2)=4w-1+3(3w+2)

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Solution for -5(w+2)=4w-1+3(3w+2) equation: 



-5(w+2)=4w-1+3(3w+2)

We move all terms to the left:

-5(w+2)-(4w-1+3(3w+2))=0

We multiply parentheses

-5w-(4w-1+3(3w+2))-10=0



We calculate terms in parentheses: -(4w-1+3(3w+2)), so:

4w-1+3(3w+2)

determiningTheFunctionDomain
4w+3(3w+2)-1

We multiply parentheses

4w+9w+6-1

We add all the numbers together, and all the variables

13w+5

Back to the equation:

-(13w+5)



We get rid of parentheses

-5w-13w-5-10=0

We add all the numbers together, and all the variables

-18w-15=0

We move all terms containing w to the left, all other terms to the right

-18w=15

w=15/-18

w=-5/6

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