-5(v+3)=6v-8+2(2v+1)

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Solution for -5(v+3)=6v-8+2(2v+1) equation: 



-5(v+3)=6v-8+2(2v+1)

We move all terms to the left:

-5(v+3)-(6v-8+2(2v+1))=0

We multiply parentheses

-5v-(6v-8+2(2v+1))-15=0



We calculate terms in parentheses: -(6v-8+2(2v+1)), so:

6v-8+2(2v+1)

determiningTheFunctionDomain
6v+2(2v+1)-8

We multiply parentheses

6v+4v+2-8

We add all the numbers together, and all the variables

10v-6

Back to the equation:

-(10v-6)



We get rid of parentheses

-5v-10v+6-15=0

We add all the numbers together, and all the variables

-15v-9=0

We move all terms containing v to the left, all other terms to the right

-15v=9

v=9/-15

v=-3/5

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