-5(v+1)=3v-2+2(3v+2)

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Solution for -5(v+1)=3v-2+2(3v+2) equation: 



-5(v+1)=3v-2+2(3v+2)

We move all terms to the left:

-5(v+1)-(3v-2+2(3v+2))=0

We multiply parentheses

-5v-(3v-2+2(3v+2))-5=0



We calculate terms in parentheses: -(3v-2+2(3v+2)), so:

3v-2+2(3v+2)

determiningTheFunctionDomain
3v+2(3v+2)-2

We multiply parentheses

3v+6v+4-2

We add all the numbers together, and all the variables

9v+2

Back to the equation:

-(9v+2)



We get rid of parentheses

-5v-9v-2-5=0

We add all the numbers together, and all the variables

-14v-7=0

We move all terms containing v to the left, all other terms to the right

-14v=7

v=7/-14

v=-1/2

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