-5(u+2)=7u-4+2(3u+1)

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Solution for -5(u+2)=7u-4+2(3u+1) equation: 



-5(u+2)=7u-4+2(3u+1)

We move all terms to the left:

-5(u+2)-(7u-4+2(3u+1))=0

We multiply parentheses

-5u-(7u-4+2(3u+1))-10=0



We calculate terms in parentheses: -(7u-4+2(3u+1)), so:

7u-4+2(3u+1)

determiningTheFunctionDomain
7u+2(3u+1)-4

We multiply parentheses

7u+6u+2-4

We add all the numbers together, and all the variables

13u-2

Back to the equation:

-(13u-2)



We get rid of parentheses

-5u-13u+2-10=0

We add all the numbers together, and all the variables

-18u-8=0

We move all terms containing u to the left, all other terms to the right

-18u=8

u=8/-18

u=-4/9

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