-5(t-3)-(t+1)=2

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Solution for -5(t-3)-(t+1)=2 equation:


Simplifying
-5(t + -3) + -1(t + 1) = 2

Reorder the terms:
-5(-3 + t) + -1(t + 1) = 2
(-3 * -5 + t * -5) + -1(t + 1) = 2
(15 + -5t) + -1(t + 1) = 2

Reorder the terms:
15 + -5t + -1(1 + t) = 2
15 + -5t + (1 * -1 + t * -1) = 2
15 + -5t + (-1 + -1t) = 2

Reorder the terms:
15 + -1 + -5t + -1t = 2

Combine like terms: 15 + -1 = 14
14 + -5t + -1t = 2

Combine like terms: -5t + -1t = -6t
14 + -6t = 2

Solving
14 + -6t = 2

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + -6t = 2 + -14

Combine like terms: 14 + -14 = 0
0 + -6t = 2 + -14
-6t = 2 + -14

Combine like terms: 2 + -14 = -12
-6t = -12

Divide each side by '-6'.
t = 2

Simplifying
t = 2

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